Aural-Aid
New member
Hi friends of SOFT!
I would like to share something with the clever community here and find out what they think. Sometime ago, I was playing around with Sabine's equation and found out that you could estimate sound absorption coefficients using RT60 instead of the ASTM C423's method of using decay rate (dB/S).
Here are the workings (I do apologise for not using mathematical symbols as the thread does not display them properly)
Thanks for reading this far and may you have a great weekend ahead!
I would like to share something with the clever community here and find out what they think. Sometime ago, I was playing around with Sabine's equation and found out that you could estimate sound absorption coefficients using RT60 instead of the ASTM C423's method of using decay rate (dB/S).
Here are the workings (I do apologise for not using mathematical symbols as the thread does not display them properly)
Let's start with Sabine's Formula (RT60)
In a reverberation chamber with materials to be tested,
Therefore, RT60 = 0.1611V/(arSr + amSm)
Finding am,
Since the surfaces of a reverberation chamber are almost perfectly reflective, ar = u where u is a very small number.
Therefore am can be approximated to
How does this method reconcile with ASTM C423's method?
ASTM C423-09a uses Sabine's equation (decay rate dB/s)
to derive
Since equation (1) and (3) are just different sides of the same equation where 0.9210d = 4ln10^6/RT60, we will focus on reconciling equation (2) and (4).
From (1)
Looking at (4)
Since am = (A2 - A1)/Sm ---(4)
where (arSr/Sm) is a small number since ar is negligible.
Therefore equation (2) and (4) are reconciled.
RT60 = 4ln10^6/c * V/A = (approx) 0.1611V/A ---(1)
where
A = Summation aiSi
ai = absorption coefficient of i
Si = surface area of i
V = is the volume of the room in m³
A = Summation aiSi
ai = absorption coefficient of i
Si = surface area of i
V = is the volume of the room in m³
In a reverberation chamber with materials to be tested,
A = Summation aiSi = arSr + amSm
where
r = of reverberation chamber (e.g. Sr = surface area of reverberation chamber in m²)
m = of material tested (e.g. am = absorption coefficient of material tested)
r = of reverberation chamber (e.g. Sr = surface area of reverberation chamber in m²)
m = of material tested (e.g. am = absorption coefficient of material tested)
Therefore, RT60 = 0.1611V/(arSr + amSm)
Finding am,
am = (0.1611V/RT60Sm) - (arSr/Sm) ---(2)
Since the surfaces of a reverberation chamber are almost perfectly reflective, ar = u where u is a very small number.
Therefore am can be approximated to
am = (approx) 0.1611V/RT60Sm
How does this method reconcile with ASTM C423's method?
ASTM C423-09a uses Sabine's equation (decay rate dB/s)
A = 0.9210 Vd/c ---(3)
to derive
a = (A2 - A1)/Sm ---(4)
where
A2 = Absorption (Sabines) of reverberation chamber with materials
A1 = Absorption (Sabines) of reverberation chamber without materials
Sm = Surface area of material
A2 = Absorption (Sabines) of reverberation chamber with materials
A1 = Absorption (Sabines) of reverberation chamber without materials
Sm = Surface area of material
Since equation (1) and (3) are just different sides of the same equation where 0.9210d = 4ln10^6/RT60, we will focus on reconciling equation (2) and (4).
From (1)
A = 0.1611V/RT60 = Summation aiSi
Looking at (4)
A1 = arSr
A2 = 0.1611V/RT60
A2 = 0.1611V/RT60
Since am = (A2 - A1)/Sm ---(4)
am = [(0.1611V/RT60) - (arSr)]/Sm
am = (0.1611V/RT60Sm) - (arSr/Sm)
am = (0.1611V/RT60Sm) - (arSr/Sm)
where (arSr/Sm) is a small number since ar is negligible.
am = (approx) 0.1611V/RT60Sm
Therefore equation (2) and (4) are reconciled.
TL;DR - Using RT60, you could estimate the sound absorption coefficient of your materials with this formula
Note: For an accurate measure, the size of the room needs to be about 200 m³.
am = (approx) 0.1611V/RT60Sm
where
am = absorption coefficient of material tested
V = is the volume of the reflective room in m³
Sm = Surface area of material tested in m²
am = absorption coefficient of material tested
V = is the volume of the reflective room in m³
Sm = Surface area of material tested in m²
Note: For an accurate measure, the size of the room needs to be about 200 m³.
Thanks for reading this far and may you have a great weekend ahead!