Missing component from treble bleed circuit...

Kyokkai

New member
Yo ppl...I sent my guitar for treble bleed at sv guitars and when i got it back, i noticed sth very weird. Normal treble bleed circuits consists of a resistor and a capacitor(soldered onto the vol pot)...but the treble bleed circuit that Mike(sv guitars) did for me only consisted of a resistor. Why is this so? Can anyone tell/explain me?
 
Why not ask him yourself? He can explain better. Just having the resistor there only raises the resistance of the pot.
 
Yo ppl...I sent my guitar for treble bleed at sv guitars and when i got it back, i noticed sth very weird. Normal treble bleed circuits consists of a resistor and a capacitor(soldered onto the vol pot)...but the treble bleed circuit that Mike(sv guitars) did for me only consisted of a resistor. Why is this so? Can anyone tell/explain me?

Erms...sorry ppl...my mistake. Wad my treble bleed circuit didnt have was a resistor, not capacitor. Sorry. But pls do tell me why is this so.
 
Having the resistor there increases the resistance of the pot, making the sound brighter overall. Perhaps he thought that the guitar need not be anymore bright as it was and did not install one. And like I said, why not ask him instead?
 
a treble bleed circuit can be done with just a capacitor, without the resistor.

But why some include a resistor with it, is to change the taper response of volume pot to work better with treble bleed mod added or to limit the signal from going too bright as the vol pot is reduced.

This resistor can be wired in series to the cap or in parallel.

Anyway, without the resistor, the treble bleed mod will still work. If really so in need of the resistor, go sim lim tower and get some to experiment. Each resistor at 30cent, buy in bulk, each cost 3cent only.
 
Mike just explained to me the same thing u ppl said. He said my pot wasn't necessary for a resistor.
 
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